Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 577: 78


$\dfrac{7}{\sqrt{35}+\sqrt {21}}$

Work Step by Step

Simplify. $ \dfrac{\sqrt 7}{\sqrt 5+\sqrt 3}$ Now, $\dfrac{\sqrt 7}{\sqrt 5+\sqrt 3}=\dfrac{\sqrt 7}{\sqrt 5+\sqrt 3} \times \dfrac{\sqrt 7}{\sqrt 7}$ or, $=\dfrac{(\sqrt7)^2}{\sqrt 7(\sqrt 5+\sqrt 3)}$ $\implies \dfrac{7}{\sqrt{35}+\sqrt {21}}$
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