Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 577: 63

Answer

$\frac{2\sqrt6}{3}$.

Work Step by Step

The given expression is $=\frac{4}{\sqrt6}$ Multiply the numerator and the denominator by $\sqrt 6$. $=\frac{4}{\sqrt6}\cdot \frac{\sqrt{6}}{\sqrt6}$ Use product rule. $=\frac{4\sqrt6}{6}$ Simplify. $=\frac{2\sqrt6}{3}$.
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