Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 577: 53

Answer

$2x \sqrt[4]{2x}$.

Work Step by Step

$=\frac{\sqrt[4]{64x^7}}{\sqrt[4]{2x^2}}$ Use quotient rule. $=\sqrt[4]{\frac{64x^7}{2x^2}}$ Simplify. $=\sqrt[4]{32x^{7-2}}$ Factor as a power of $4$. $=\sqrt[4]{2^4\cdot 2x^4x}$ Use product rule. $=\sqrt[4]{2^4x^4}\cdot \sqrt[4]{2x}$ Simplify. $=2x \sqrt[4]{2x}$.
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