Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 577: 80



Work Step by Step

Simplify. $ \sqrt{2x+4}=6$ Take square on both sides. we have, $ (\sqrt{2x+4})^2=(6)^2$ or, $2x+4=36 \implies 2x=36-4$ Thus, $x=16$
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