Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 577: 57

Answer

$-83+3\sqrt{35}$.

Work Step by Step

The given expression is $=(\sqrt{7}-3\sqrt{5})(\sqrt{7}+6\sqrt{5})$ Use the FOIL method. $=\sqrt{7}\cdot\sqrt{7}+6\sqrt{7}\cdot \sqrt{5}-3\sqrt5\cdot \sqrt{7}-18\sqrt5\cdot\sqrt{5}$ Use product rule. $=(\sqrt{7})^2+6\sqrt{35}-3\sqrt{35}-18(\sqrt5)^2$ Simplify. $=7+3\sqrt{35}-90$ $=-83+3\sqrt{35}$.
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