Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 577: 45

Answer

$9\sqrt{2}$.

Work Step by Step

The given expression is $=5\sqrt{18}-3\sqrt{8}$ Factor radicands as a perfect square. $=5\sqrt{3^2\cdot 2}-3\sqrt{2^2\cdot 2}$ Simplify. $=5\cdot 3\sqrt{2}-3\cdot 2\sqrt{2}$ $=15\sqrt{2}-6\sqrt{2}$ Use the distributive property. $=(15-6)\sqrt{2}$ Simplify. $=9\sqrt{2}$.
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