Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 577: 69

Answer

$\frac{5\sqrt[5]{xy^4}}{2xy}$.

Work Step by Step

The given expression is $=\frac{5}{\sqrt[5]{32x^4y}}$ Multiply the numerator and the denominator by $\sqrt[5]{xy^4}$ $=\frac{5}{\sqrt[5]{32x^4y}}\cdot \frac{\sqrt[5]{xy^4}}{\sqrt[5]{xy^4}}$ Use product rule. $=\frac{5\sqrt[5]{xy^4}}{\sqrt[5]{32x^4y\cdot xy^4}}$ Simplify. $=\frac{5\sqrt[5]{xy^4}}{\sqrt[5]{2^5x^5y^5}}$ $=\frac{5\sqrt[5]{xy^4}}{2xy}$.
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