Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 577: 51

Answer

$2 \sqrt{6}$.

Work Step by Step

$=\frac{\sqrt{48}}{\sqrt{2}}$ Use quotient rule. $=\sqrt{\frac{48}{2}}$ Simplify. $=\sqrt{24}$ Factor as a perfect square. $=\sqrt{2^2\cdot 6}$ Use product rule. $=\sqrt{2^2}\cdot \sqrt{6}$ Simplify. $=2 \sqrt{6}$.
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