Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 577: 50

Answer

$\frac{y\sqrt[4]{3 y}}{2x^5}$.

Work Step by Step

$=\sqrt[4]{\frac{3y^5}{16x^{20}}}$ Use quotient rule. $=\frac{\sqrt[4]{3y^5}}{\sqrt[4]{16x^{20}}}$ $=\frac{\sqrt[4]{3y^4\cdot y}}{\sqrt[4]{2^4(x^{5})^4}}$ Use product rule. $=\frac{\sqrt[4]{y^4}\sqrt[4]{3 y}}{\sqrt[4]{2^4(x^{5})^4}}$ Simplify. $=\frac{y\sqrt[4]{3 y}}{2x^5}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.