Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 577: 71



Work Step by Step

Simplify. $\dfrac{\sqrt7}{\sqrt5+\sqrt3}$ Now, $\dfrac{\sqrt7}{\sqrt5+\sqrt3}=\dfrac{\sqrt7(\sqrt5-\sqrt3)}{(\sqrt5+\sqrt3)(\sqrt5-\sqrt3)}$ or, $=\dfrac{\sqrt7\sqrt5-\sqrt7\sqrt3)}{(\sqrt5)^2-(\sqrt3)^2}$ or, $=\dfrac{\sqrt{35}-\sqrt{21}}{2}$
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