Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 577: 47

Answer

$-8\sqrt[3]{6}$.

Work Step by Step

The given expression is $=2\sqrt[3]{6}-5\sqrt[3]{48}$ Factor radicands as a perfect cube. $=2\sqrt[3]{6}-5\sqrt[3]{2^3\cdot 6}$ Simplify. $=2\sqrt[3]{6}-5\cdot 2\sqrt[3]{ 6}$ $=2\sqrt[3]{6}-10\sqrt[3]{ 6}$ Use the distributive property. $=(2-10)\sqrt[3]{6}$ Simplify. $=-8\sqrt[3]{6}$.
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