Answer
See graph
Work Step by Step
Given
\begin{equation}
y>2(x+7)(x-4)=2(x^2+3x-28)= 2x^2+6x-56.
\end{equation} First, we will sketch the graph of the quadratic using a dashed curve because there is no "equal to" part.
Next, pick $(0,0)$ as a test point, we find that it does satisfy the inequality, so we will shade the points above the parabola.
