Answer
$\frac{4\sqrt[3] 9 }{3}$
Work Step by Step
$\frac{4}{\sqrt[3] 3}=\frac{4 \times \sqrt[3] (3^{2}) }{\sqrt[3] 3 \times \sqrt[3] (3^{2})}=\frac{4\times\sqrt[3] (3^{2}) }{\sqrt[3] (3\times3^{2})}=\frac{4\sqrt[3] (3^{2}) }{\sqrt[3] 27}=\frac{4\sqrt[3] 9 }{3}$
We know that $\sqrt[3] 27=3$, because $3^{3}=27$.