Chapter 7 - Section 7.5 - Rationalizing Denominators and Numerators of Radical Expressions - Exercise Set - Page 445: 69

$\dfrac{3x^2}{10\sqrt[3]{9x}}$

Rationalizing the numerator of $ \dfrac{\sqrt[3]{3x^5}}{10} $ results to \begin{array}{l} \dfrac{\sqrt[3]{3x^5}}{10} \cdot \dfrac{\sqrt[3]{9x}}{\sqrt[3]{9x}} \\\\= \dfrac{\sqrt[3]{27x^6}}{10\sqrt[3]{9x}} \\\\= \dfrac{3x^2}{10\sqrt[3]{9x}} .\end{array}