Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.5 - Rationalizing Denominators and Numerators of Radical Expressions - Exercise Set - Page 445: 32

Answer

$\dfrac{2\sqrt[5]{m^4n^{2}}}{m^{2}n^{3}}$

Work Step by Step

Rationalizing the denominator of $ \sqrt[5]{\dfrac{32}{m^6n^{13}}} $ results to \begin{array}{l} \sqrt[5]{\dfrac{32}{m^6n^{13}}} \cdot \sqrt[5]{\dfrac{m^4n^{2}}{m^4n^{2}}} \\\\= \sqrt[5]{\dfrac{32m^4n^{2}}{m^{10}n^{15}}} \\\\= \dfrac{2\sqrt[5]{m^4n^{2}}}{m^{2}n^{3}} .\end{array}
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