Answer
$\dfrac{5}{\sqrt[3]{10}}$
Work Step by Step
Rationalizing the numerator of $
\sqrt[3]{\dfrac{25}{2}}
$ results to
\begin{array}{l}
\sqrt[3]{\dfrac{25}{2}}
\cdot
\sqrt[3]{\dfrac{5}{5}}
\\\\=
\sqrt[3]{\dfrac{125}{10}}
\\\\=
\dfrac{5}{\sqrt[3]{10}}
.\end{array}