Answer
$\dfrac{\sqrt{2x}}{8x}$
Work Step by Step
Rationalizing the denominator of $
\dfrac{1}{\sqrt{32x}}
$ results to
\begin{array}{l}
\dfrac{1}{\sqrt{16\cdot2x}}
\cdot
\dfrac{\sqrt{2x}}{\sqrt{2x}}
\\\\=
\dfrac{\sqrt{2x}}{\sqrt{16\cdot4x^2}}
\\\\=
\dfrac{\sqrt{2x}}{4\cdot2x}
\\\\=
\dfrac{\sqrt{2x}}{8x}
.\end{array}