Chapter 7 - Section 7.5 - Rationalizing Denominators and Numerators of Radical Expressions - Exercise Set - Page 445: 12

$\dfrac{5\sqrt[3]{9y^2}}{3y}$

Rationalizing the denominator of $ \dfrac{5}{\sqrt[3]{3y}} $ results to \begin{array}{l} \dfrac{5}{\sqrt[3]{3y}} \cdot \dfrac{\sqrt[3]{9y^2}}{\sqrt[3]{9y^2}} \\\\= \dfrac{5\sqrt[3]{9y^2}}{\sqrt[3]{27y^3}} \\\\= \dfrac{5\sqrt[3]{9y^2}}{3y} .\end{array}