Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.5 - Rationalizing Denominators and Numerators of Radical Expressions - Exercise Set: 56



Work Step by Step

Rationalizing the numerator of $ \sqrt{\dfrac{3}{2}} $ results to \begin{array}{l} \sqrt{\dfrac{3}{2}} \cdot \sqrt{\dfrac{3}{3}} \\\\= \sqrt{\dfrac{9}{6}} \\\\= \dfrac{3}{\sqrt{6}} .\end{array}
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