Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.5 - Rationalizing Denominators and Numerators of Radical Expressions - Exercise Set - Page 445: 31

Answer

$\dfrac{2\sqrt[4]{9x}}{3x^2}$

Work Step by Step

Rationalizing the denominator of $ \sqrt[4]{\dfrac{16}{9x^7}} $ results to \begin{array}{l} \sqrt[4]{\dfrac{16}{9x^7}} \cdot \sqrt[4]{\dfrac{9x}{9x}} \\\\= \sqrt[4]{\dfrac{16\cdot9x}{81x^8}} \\\\= \dfrac{2\sqrt[4]{9x}}{3x^2} .\end{array}
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