Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.5 - Rationalizing Denominators and Numerators of Radical Expressions - Exercise Set: 57



Work Step by Step

Rationalizing the numerator of $ \sqrt{\dfrac{18}{5}} $ results to \begin{array}{l} \sqrt{\dfrac{9\cdot2}{5}} \\\\= 3\sqrt{\dfrac{2}{5}} \\\\= 3\sqrt{\dfrac{2}{5}} \cdot \sqrt{\dfrac{2}{2}} \\\\= 3\sqrt{\dfrac{4}{10}} \\\\= 3\cdot2\sqrt{\dfrac{1}{10}} \\\\= \dfrac{6}{\sqrt{10}} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.