Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.5 - Rationalizing Denominators and Numerators of Radical Expressions - Exercise Set: 47



Work Step by Step

Rationalizing the denominator of $ \dfrac{\sqrt{a}+1}{2\sqrt{a}-\sqrt{b}} $ results to \begin{array}{l} \dfrac{\sqrt{a}+1}{2\sqrt{a}-\sqrt{b}} \cdot \dfrac{\sqrt{a}+\sqrt{b}}{2\sqrt{a}+\sqrt{b}} \\\\= \dfrac{(\sqrt{a})(\sqrt{a})+(\sqrt{a})(\sqrt{b})+(1)(\sqrt{a})+(1)(\sqrt{b})}{(2\sqrt{a})^2-(\sqrt{b})^2} \\\\= \dfrac{(\sqrt{a})(\sqrt{a})+(\sqrt{a})(\sqrt{b})+(1)(\sqrt{a})+(1)(\sqrt{b})}{(2\sqrt{a})^2-(\sqrt{b})^2} \\\\= \dfrac{a+\sqrt{ab}+\sqrt{a}+\sqrt{b}}{4a-b} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.