Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.5 - Rationalizing Denominators and Numerators of Radical Expressions - Exercise Set: 67



Work Step by Step

Rationalizing the numerator of $ \sqrt[3]{\dfrac{7}{8}} $ results to \begin{array}{l} \sqrt[3]{\dfrac{7}{8}} \cdot \sqrt[3]{\dfrac{7^2}{7^2}} \\\\= \sqrt[3]{\dfrac{7^3}{8\cdot7^2}} \\\\= \dfrac{7}{2\sqrt[3]{49}} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.