Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.5 - Rationalizing Denominators and Numerators of Radical Expressions - Exercise Set: 43



Work Step by Step

Rationalizing the denominator of $ \dfrac{-7}{\sqrt{x}-3} $ results to \begin{array}{l} \dfrac{-7}{\sqrt{x}-3} \cdot \dfrac{\sqrt{x}+3}{\sqrt{x}+3} \\\\= \dfrac{-7\sqrt{x}-21}{(\sqrt{x})^2-(3)^2} \\\\= \dfrac{-7\sqrt{x}-21}{x-9} .\end{array}
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