Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.7 - Factoring by Special Products - Exercise Set - Page 309: 59



Work Step by Step

Using factoring techniques, then, \begin{array}{l} x^2-10x+25-y^2 \\= (x^2-10x+25)-y^2 \\= (x-5)^2-y^2 \\= [(x-5)+y][(x-5)-y] \\= (x-5+y)(x-5-y) .\end{array}
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