Answer
$(2x+3y)(4x^2-6xy+9y^2)$
Work Step by Step
Using $a^3+b^3=(a+b)(a^2-ab+b^2)$ or the factoring of the difference of 2 cubes, then,
\begin{array}{l}
8x^3+27y^3
\\=
[(2x)+(3y)][(2x)^2-(2x)(3y)+(3y)^2]
\\=
(2x+3y)(4x^2-6xy+9y^2)
.\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 5 - Section 5.7 - Factoring by Special Products - Exercise Set - Page 309: 49
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