## Intermediate Algebra (6th Edition)

$b(a+2b)(a^2-2ab+4b^2)$
Factoring the $GCF= b$ results to $b(a^3+8b^3)$. Using $a^3+b^3=(a+b)(a^2-ab+b^2)$, or the factoring of the sum/difference of two cubes, then, \begin{array}{l} b(a^3+8b^3) \\= b[(a)+(2b)][(a)^2-(a)(2b)+(2b)^2) \\= b(a+2b)(a^2-2ab+4b^2) .\end{array}