## Intermediate Algebra (6th Edition)

$2y(3x+1)(3x-1)$
Factoring the $GCF= 2y$ results to $2y(9x^2-1)$. Using $a^2-b^2=(a+b)(a-b)$ or the factoring of the difference of 2 squares, then, \begin{array}{l} 2y(9x^2-1) \\= 2y(3x+1)(3x-1) .\end{array}