#### Answer

$12(y+3)(y-3)$

#### Work Step by Step

Factoring the $GCF=
12x
$ results to $
12x(y^2-9)
$. Using $a^2-b^2=(a+b)(a-b)$ or the factoring of the difference of 2 squares, then,
\begin{array}{l}
12x(y^2-9)
\\=
12(y+3)(y-3)
.\end{array}

Published by
Pearson

ISBN 10:
0321785045

ISBN 13:
978-0-32178-504-6

$12(y+3)(y-3)$

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