Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.7 - Factoring by Special Products - Exercise Set - Page 309: 31



Work Step by Step

Using $a^3\pm b^3=(a\pm b)(a^2\mp ab+b^2)$, or the factoring of the sum/difference of two cubes, then, \begin{array}{l} p^3+125q^3 \\= (p+5q)[(p)^2-(p)(5q)+(5q)^2) \\= (p+5q)(p^2-5pq+25q^2) .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.