Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.7 - Factoring by Special Products - Exercise Set: 32

Answer

$(p+5q)(p^2-5pq+25q^2)$

Work Step by Step

Using $a^3+b^3=(a+b)(a^2-ab+b^2)$ or the factoring of the sum/difference of 2 cubes, then the factored form of the the given expression, $ p^3+125q^3 $, is \begin{array}{l} (p+5q)[(p)^2-p(5q)+(5q)^2] \\\\= (p+5q)(p^2-5pq+25q^2) .\end{array}
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