Answer
$2(5y-2x)(25y^2+10xy+4x^2)$
Work Step by Step
Factoring the $GCF=
2
$ results to $
2(125y^3-8x^3)
$. Using $a^3+b^3=(a+b)(a^2-ab+b^2)$, or the factoring of the sum/difference of two cubes, then,
\begin{array}{l}
2(125y^3-8x^3)
\\=
2[(5y)+(-2x)][(5y)^2-(5y)(-2x)+(-2x)^2)
\\=
2(5y-2x)(25y^2+10xy+4x^2)
.\end{array}
