## Intermediate Algebra (6th Edition)

$4(4x+5)(4x-5)$
Factoring the $GCF= 4$ results to $4(16x^2-25)$. Using $a^2-b^2=(a+b)(a-b)$ or the factoring of the difference of two squares, then, \begin{array}{l} 4(16x^2-25) \\= 4(4x+5)(4x-5) .\end{array}