Answer
$4(x-3)(x+3)$
Work Step by Step
Factoring the $GCF=
4
$ results to $
4(x^2-9)
$. Using $a^2-b^2=(a+b)(a-b)$ or the factoring of the difference of two squares, then,
\begin{array}{l}
4(x^2-9)
\\=
4(x-3)(x+3)
.\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 5 - Section 5.7 - Factoring by Special Products - Exercise Set - Page 309: 20
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