## Intermediate Algebra (6th Edition)

$(y-5)(y+9)$
Using $a^2-b^2=(a+b)(a-b)$ or the factoring of the difference of two squares, then, \begin{array}{l} (y+2)^2-49 \\= [(y+2)-7][(y+2)+7] \\= (y-5)(y+9) .\end{array}