Answer
$x^{6t-1}$
Work Step by Step
We are given the expression $\frac{x^{3t}\times x^{4t-1}}{x^{t}}$.
To simplify the numerator we can use the product rule, which holds that $a^{m}\times a^{n}=a^{m+n}$ (where a is a real number, and m and n are positive integers).
$\frac{x^{3t}\times x^{4t-1}}{x^{t}}=\frac{x^{3t+4t-1}}{x^{t}}=\frac{x^{7t-1}}{x^{t}}$
Next, we can use the quotient rule to simplify, which holds that $\frac{a^{m}}{a^{n}}=a^{m-n}$ (where a is a nonzero real number, and m and n are integers).
$\frac{x^{7t-1}}{x^{t}}=x^{7t-1-t}=x^{6t-1}$