Answer
$\frac{1}{8}$
Work Step by Step
We are given the expression $2^{-3}$. In general, $a^{-n}=\frac{1}{a^{n}}$, where a is a nonzero real number and n is a positive integer.
Therefore, $2^{-3}=\frac{1}{2^{3}}=\frac{1}{2\times2\times2}=\frac{1}{8}$