Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.1 - Exponents and Scientific Notation - Exercise Set - Page 262: 48



Work Step by Step

We are given the expression $\frac{3s^{3}}{15s^{-3}}$. To simplify, we can use the quotient rule, which holds that $\frac{a^{m}}{a^{n}}=a^{m-n}$ (where a is a nonzero real number, and m and n are integers). Therefore, $\frac{3s^{3}}{15s^{-3}}=\frac{3}{15}\times s^{3-(-3)}=\frac{1}{5}\times s^{3+3}=\frac{s^{6}}{5}$.
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