Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.1 - Exponents and Scientific Notation - Exercise Set - Page 262: 13

Answer

$-20x^{2}y$

Work Step by Step

We are given the expression $(4xy)(-5x)$. $(4xy)\times(-5x)=(4\times-5)\times(x\times x)\times(y)$ We can use the product rule to simplify the middle term, which holds that $a^{m}\times a^{n}=a^{m+n}$. Therefore, $(4\times-5)\times(x\times x)\times(y)=-20\times x^{1+1}\times y=-20x^{2}y$
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