## Intermediate Algebra (6th Edition)

$\frac{1}{y^{14}}$
We are given the expression $\frac{y^{-7}y}{y^{-8}}$. To simplify, we can first use the product rule, which holds that $a^{m}\times a^{n}=a^{m+n}$. $\frac{y^{-7+1}}{y^{-8}}=\frac{y^{-6}}{y^{8}}$ Next, we can use the quotient rule, which holds that $\frac{a^{m}}{a^{n}}=a^{m-n}$. $y^{-6-8}=y^{-14}$ Finally, we know that $a^{-n}=\frac{1}{a^{n}}$, so $y^{-14}=\frac{1}{y^{14}}$