Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.1 - Exponents and Scientific Notation - Exercise Set - Page 262: 78

Answer

$36a^{5}b^{10}$

Work Step by Step

We are given the expression $(-6a^{4}b)(2b^{3})(-3ab^{6})$. We can simplify by first grouping like terms. $(-6\times2\times-3)\times(a^{4}\times a)\times(b\times b^{3}\times b^{6})$ Next we can use the product rule, which holds that $a^{m}\times a^{n}=a^{m+n}$ (where a is a real number, and m and n are positive integers). $36\times (a^{4+1})\times (b^{1+3+6})=36a^{5}b^{10}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.