## Intermediate Algebra (6th Edition)

$n^{23}$
We are given the expression $n\times n^{10}\times n^{12}$. We can use the product rule to simplify, which holds that $a^{m}\times a^{n}=a^{m+n}$. More generally, the product of any number of exponential expressions with a common base is the common base raised to a power equal to the sum of the exponents of the factors. Therefore, $n\times n^{10}\times n^{12}=n^{1+10+12}=n^{23}$