Answer
$-7a^{2}c^{6}$
Work Step by Step
We are given the expression $\frac{49a^{3}bc^{14}}{-7abc^{8}}$.
We can simplify this expression by using the quotient rule, which holds that $\frac{a^{m}}{a^{n}}=a^{m-n}$ (where a is a nonzero real number, and m and n are integers).
$\frac{49a^{3}bc^{14}}{-7abc^{8}}=(\frac{49}{-7})\times(a^{3-1})\times(b^{1-1})\times(c^{14-8})=-7a^{2}b^{0}c^{6}=-7a^{2}c^{6}$
