## Intermediate Algebra (6th Edition)

We are given the expression $4^{0}+4x^{0}$. $4^{0}+4x^{0}=1+4(x^{0})=1+4\times1=5$ In general, $a^{0}=1$ when a is nonzero. In the second term, 4 and x are not in parentheses, so only x (the base of the exponent) is evaluated by the exponent.