Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.1 - Exponents and Scientific Notation - Exercise Set - Page 262: 30

Answer

$a^{3} b$

Work Step by Step

We are given the expression $\frac{a^{12}b^{2}}{a^{9}b}$. We can simplify this expression by using the quotient rule, which holds that $\frac{a^{m}}{a^{n}}=a^{m-n}$ (where a is a nonzero real number, and m and n are integers). $\frac{a^{12}b^{2}}{a^{9}b}=(a^{12-9})\times (b^{2-1})=a^{3} b$
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