Intermediate Algebra (6th Edition)

$\frac{x}{16}$
We are given the expression $2^{-4}\times x$. To simplify this into a positive exponent, we know that $a^{-n}=\frac{1}{a^{n}}$ (where a is a nonzero real number and n is a positive integer). $2^{-4}\times x=\frac{x}{2^{4}}=\frac{x}{16}$