Answer
-2
Work Step by Step
We are given the expression $3^{0}-3t^{0}$.
$3^{0}-3t^{0}=1-3(t^{0})=1-3\times1=-2$
In general, $a^{0}=1$ when a is nonzero. In the second term, 3 and t are not in parentheses, so only t (the base of the exponent) is evaluated by the exponent.