## Intermediate Algebra (6th Edition)

Published by Pearson

# Chapter 5 - Section 5.1 - Exponents and Scientific Notation - Exercise Set - Page 262: 65

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#### Work Step by Step

We are given the expression $3^{0}-3t^{0}$. $3^{0}-3t^{0}=1-3(t^{0})=1-3\times1=-2$ In general, $a^{0}=1$ when a is nonzero. In the second term, 3 and t are not in parentheses, so only t (the base of the exponent) is evaluated by the exponent.

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