Answer
$48, 24, 12, 6, 3$
Work Step by Step
The general term $a_n$ of a geometric sequence is given by $a_n = a_1r^{n-1}$ where $a_1$ is the first term and $r$ is the common ratio.
We plug in $n = 1, 2, 3, 4, 5$ to find the first five terms of the geometric sequence
$a_1 = 48\cdot\frac{1}{2}^{1-1} = 48\cdot\frac{1}{2}^0=48\cdot1=48$
$a_2 = 48\cdot\frac{1}{2}^{2-1} = 48\cdot\frac{1}{2}^1=48\cdot\frac{1}{2}=24$
$a_3 = 48\cdot\frac{1}{2}^{3-1} = 48\cdot\frac{1}{2}^2=48\cdot\frac{1}{4}=12$
$a_4 = 48\cdot\frac{1}{2}^{4-1} = 48\cdot\frac{1}{2}^3=48\cdot\frac{1}{8}=6$
$a_5 = 48\cdot\frac{1}{2}^{5-1} = 48\cdot\frac{1}{2}^4=48\cdot\frac{1}{16}=3$
