Answer
$-2,-4,-8,-16,-32$
Work Step by Step
The general term $a_n$ of a geometric sequence is given by $a_n = a_1r^{n-1}$ where $a_1$ is the first term and $r$ is the common ratio.
We plug in $n = 1, 2, 3, 4, 5$ to find the first five terms of the geometric sequence
$a_1 = -2\cdot2^{1-1} = -2\cdot2^0=-2\cdot1=-2$
$a_2 = -2\cdot2^{2-1} = -2\cdot2^1=-2\cdot2=-4$
$a_3 = -2\cdot2^{3-1} = -2\cdot2^2=-2\cdot4=-8$
$a_4 = -2\cdot2^{4-1} = -2\cdot2^3=-2\cdot8=-16$
$a_5 = -2\cdot2^{5-1} = -2\cdot2^4=-2\cdot16=-32$
