Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.2 - Arithmetic and Geometric Sequences - Exercise Set - Page 646: 12

Answer

$243$

Work Step by Step

To find the $n$th term of a geometric sequence, we use the formula $a_n = a_1 \cdot r^{n-1}$ where $a_1$ is the first term and $r$ is the common ratio. $a_5 = 3\cdot3^{5-1} = 3\cdot3^4 = 3\cdot81 = 243$
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